The Rotary Piston Engine Mathematical formulas:
A engine is not a engine, without mathematics to back it up!
The Rotary Piston Engine can be calculated to a point of true output of mechanical work.
The TR1 19.29 cu/in Rotary engine Engine design
Piston vane area 5.* 2 =1in/sq moving the rotor
Rotor size 6" diameter x 2" width, rotor displacement ((3^2*pi)*2)=56.54866776 cu/in
Rotary housing 7 " Inner diameter, housing displacement ((3.5^2*pi)*2)=79.96902001cu/in
Total piston vane movement in a 360 deg rotation. (((3.5^2*pi)*2)-((3^2*pi)*2))=20.42035225 cu/in
340 degree power stroke displacement ((20.42035225/360)*340)=19.28588823 cu/in
compressor pump piston size 2.5 diameter, total area (1.25^2*pi)=4.908738521 in/sq
compressor stoke 2.25" with compression ratio of 10:1
Combustion chamber size 1.1025 cu/in
Combustion chamber pressure limit : 0-6000 psi
6" Rotor output from 3" crank shaft constant
1" Crank shaft.
Torque output from combustion of fuel at Top Dead Center (TDC) output port:
Torque = ((psi x piston area) x crank)
Piston Area (.5" x 2")=1in/sq Crank= (6"diameter rotor / 2)=3
Combustion area= 1.1025cu/in
Rotor movement from o degree at combustion port to 30degree = 1cu/in of output
PSI : 500 1000 1500 2000 2500 3000 3500 4000 4500 5000 5500 6000
Rotor movement
Start 0deg - in/lb : 1500 3000 4500 6000 7500 9000 10500 12000 13500 15000 16500 18000
End 30deg - in/lb : 750 1500 2250 3000 3750 4500 5250 6000 6750 7500 8250 9000
Average - in/lb : 1125 3750 3375 4500 5625 6750 7875 9000 10125 11250 12375 13500
340deg - PSI : 12.5 25.0 37.5 50.0 62.5 75.0 87.5 100.0 1i2.5 125.0 137.5 150.0
The efficiency of this engine design, is also related to how efficient the seals are in the rotor assy.
Pressure leaks would be a important fact for this engine design, even with the worst leakage design this will sill run.
At 1470 psi and .024L combustion of fuel ,the total moles needed per revolution of engine is:
The Rotary Piston Engine can be calculated to a point of true output of mechanical work.
The TR1 19.29 cu/in Rotary engine Engine design
Piston vane area 5.* 2 =1in/sq moving the rotor
Rotor size 6" diameter x 2" width, rotor displacement ((3^2*pi)*2)=56.54866776 cu/in
Rotary housing 7 " Inner diameter, housing displacement ((3.5^2*pi)*2)=79.96902001cu/in
Total piston vane movement in a 360 deg rotation. (((3.5^2*pi)*2)-((3^2*pi)*2))=20.42035225 cu/in
340 degree power stroke displacement ((20.42035225/360)*340)=19.28588823 cu/in
compressor pump piston size 2.5 diameter, total area (1.25^2*pi)=4.908738521 in/sq
compressor stoke 2.25" with compression ratio of 10:1
Combustion chamber size 1.1025 cu/in
Combustion chamber pressure limit : 0-6000 psi
6" Rotor output from 3" crank shaft constant
1" Crank shaft.
Torque output from combustion of fuel at Top Dead Center (TDC) output port:
Torque = ((psi x piston area) x crank)
Piston Area (.5" x 2")=1in/sq Crank= (6"diameter rotor / 2)=3
Combustion area= 1.1025cu/in
Rotor movement from o degree at combustion port to 30degree = 1cu/in of output
PSI : 500 1000 1500 2000 2500 3000 3500 4000 4500 5000 5500 6000
Rotor movement
Start 0deg - in/lb : 1500 3000 4500 6000 7500 9000 10500 12000 13500 15000 16500 18000
End 30deg - in/lb : 750 1500 2250 3000 3750 4500 5250 6000 6750 7500 8250 9000
Average - in/lb : 1125 3750 3375 4500 5625 6750 7875 9000 10125 11250 12375 13500
340deg - PSI : 12.5 25.0 37.5 50.0 62.5 75.0 87.5 100.0 1i2.5 125.0 137.5 150.0
The efficiency of this engine design, is also related to how efficient the seals are in the rotor assy.
Pressure leaks would be a important fact for this engine design, even with the worst leakage design this will sill run.
At 1470 psi and .024L combustion of fuel ,the total moles needed per revolution of engine is:
